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(2+3i)(5-4i)=10-8i+15i-12i^2
We move all terms to the left:
(2+3i)(5-4i)-(10-8i+15i-12i^2)=0
We add all the numbers together, and all the variables
-(10-8i+15i-12i^2)+(3i+2)(-4i+5)=0
We get rid of parentheses
12i^2+8i-15i+(3i+2)(-4i+5)-10=0
We multiply parentheses ..
12i^2+(-12i^2+15i-8i+10)+8i-15i-10=0
We add all the numbers together, and all the variables
12i^2+(-12i^2+15i-8i+10)-7i-10=0
We get rid of parentheses
12i^2-12i^2+15i-8i-7i+10-10=0
We add all the numbers together, and all the variables
=0
i=0/1
i=0
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